The radical,C_6H_5CH_2^{bullet},is aromatic b | vedclass

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Question

(A) The benzyl radical $(C_6H_5CH_2^{\bullet})$ consists of a benzene ring attached to a $CH_2^{\bullet}$ group.The benzene ring has $6$ carbon atoms,

Vedclass · Accepted Answer

$7 \ p$-orbitals and $7$ unpaired electrons

Vedclass · Answer

(A) The benzyl radical $(C_6H_5CH_2^{\bullet})$ consists of a benzene ring attached to a $CH_2^{\bullet}$ group.The benzene ring has $6$ carbon atoms,each contributing one $p$-orbital to the delocalized $\pi$-system,containing $6 \pi$-electrons.The exocyclic carbon atom $(CH_2^{\bullet})$ is $sp^2$ hybridized and possesses one $p$-orbital containing one unpaired electron.Therefore,the total number of $p$-orbitals involved in conjugation is $6 + 1 = 7$.The total number of electrons in these $p$-orbitals is $6$ (from the ring) $+ 1$ (unpaired electron) $= 7$.However,the aromaticity is determined by the $6 \pi$-electrons in the ring,and the radical is stabilized by resonance with the ring. The question asks for the characteristics that make it aromatic; it has $7$ $p$-orbitals in total (forming a conjugated system) and $7$ electrons in these $p$-orbitals (including the radical electron).

The radical,$C_6H_5CH_2^{\bullet}$,is aromatic because it has

Similar Questions

Identify the number of aromatic compounds from the following structures:
$(I)$ Cyclopentadiene
$(II)$ Cyclooctatetraene
$(III)$ Borazine $(B_3N_3H_6)$
$(IV)$ $1,4-$diboracyclohexa$-2,5-$diene

Which of the following statements are correct?
$I$. In nitrating mixture,nitric acid participates as an acid.
$II$. $\sigma$-complex is the intermediate substance in electrophilic substitution of benzene.
$III$. Benzene on Friedel-Crafts alkylation with $n$-propyl chloride gives isopropyl benzene.

The order of reactivity of the following compounds towards electrophilic substitution will be - [where $\phi = C_6H_5$]:
$I. \phi-CH_3$
$II. \phi-CH_2-CH_3$
$III. \phi-CH(CH_3)_2$
$IV. \phi-C(CH_3)_3$

Are all $ortho$ and $para$ directing groups activators? Give examples.

Assertion : Benzene exhibits two different bond lengths, due to $C-C$ single and $C=C$ double bonds.
Reason : Actual structure of benzene is a hybrid of the following two structures.

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